Serial No. 334.
Folding Cot made by Hollow Rectangular Pipe (Autodesk Inventor 2018 Tutorial)
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For the calculation procedure, go through the following steps.
Let us consider a hollow rectangular mild steel tube or pipe of dimension 38.1mm × 38.1mm.× 1.5875mm.
(1.5” x 1.5” x 0.0625”) As shown in fig. below. Let us calculate the weight of the pipe having a 6-meter length.
| |
| Hollow Square steel section. |
Here, thickness T = 1.5875mm. breadth B = 38.1mm, depth D = 38.1mm., and length L =6m.
| |
| Hollow Square Stainless Steel tube. |
![clip_image003[10]](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiDjUWzu7n1LPFg-9pNuR6quxaCrWmWxohkr0pCZwW8ZdUw1xMy4KOPpEuqw55uP2LMhql-KX7Xa5DO7PPSfxQxnkgKDmQrV1P2lUC60KKzLyszpJbw_h8tLoageUCR0u7lTV-jGzTpcixh/s225/ms-rectangular-hollow-section.jpg "clip_image003[10]")
First, we will calculate the sectional area in two parts, the orange-colored part area as A1, and green colored part area as A2.
Method: 1
First, we will calculate the total area inclusive of the hollow part, and then we will deduct the inner hollow portion (shown in green color) of the pipe.
Area a1 =[ B × D]
= [38.1 mm. × 38.1 mm.] = 1451.61 square mm.
a1 = 0.001452 sq meter.
Area a2 = [{ B - (2T)} × { D - ( 2T)}]
= [{ 38.1 -( 2 × 1.5875)} × { 38.1 - (2 × 1.5875)}]
= [ 34.925 mm.× 34.925 mm.] = 1219.755625 square mm.
( i.e. inner green hollow part )
a2 = 0.001219756 sq meter.
Now, the total sectional area
A = [a1 – a2]
= [0.001452 — 0.001219756] sq meter.
A = 0.000232244 square meter.
Note: We got the same area (A ) as calculated before.
Volume = [area × length]
= [0.000232244 ×6]
V = 0.001393464 cubic meter.
So, the weight of the hollow square Stainless Steel 316 pipe of length 6 meters & Thickness Gauge 16.
= [volume × density]
= [0.001393464 × 7980]
= 11.1198 kg.
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For the calculation procedure, go through the following steps.
Let us consider a hollow rectangular mild steel tube or pipe of dimension 38.1mm × 38.1mm.× 1.27mm.
(1.5” x 1.5” x 0.05”) As shown in fig. below. Let us calculate the weight of the pipe having a 6-meter length.
| |
| Hollow Square steel section. |
Here, thickness T = 1.27 mm. breadth B = 38.1 mm, depth D = 38.1 mm., and length L =6 m.
| |
| Hollow Square Stainless Steel tube. |
First, we will calculate the sectional area in two parts, the orange-colored part area as A1, and green colored part area as A2.
Method: 1
First, we will calculate the total area inclusive of the hollow part, and then we will deduct the inner hollow portion (shown in green color) of the pipe.
Area a1 =[ B × D]
= [38.1 mm. × 38.1 mm.] = 1451.61 square mm.
a1 = 0.001452 sq meter.
Area a2 = [{ B - (2T)} × { D - ( 2T)}]
= [{ 38.1 -( 2 × 1.27)} × { 38.1 - (2 × 1.27)}]
= [ 35.56 mm.× 35.56 mm.] = 1264.5136 square mm.
( i.e. inner green hollow part )
a2 = 0.0012645 sq meter.
Now, the total sectional area
A = [a1 – a2]
= [0.001452 — 0.0012645] sq meter.
A = 0.0001875 square meter.
Note: We got the same area (A ) as calculated before.
Volume = [area × length]
= [0.0001875 ×6]
V = 0.001125 cubic meter.
So, the weight of the hollow square Stainless Steel 316 pipe of length 6 meters & Thickness Gauge 18.
= [volume × density]
= [0.001125 × 7980]
= 8.9775 kg.
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For the calculation procedure, go through the following steps.
Let us consider a hollow rectangular mild steel tube or pipe of dimension 12.7mm × 25.4mm.× 1.5875mm.
(0.5” x 1” x 0.0625”) As shown in fig. below. Let us calculate the weight of the pipe having a 6-meter length.
| |
| Hollow Rectangle steel section. |
Here, thickness T = 1.5875mm. breadth B = 12.7mm, depth D = 25.4mm., and length L =6m.
| |
| Hollow Rectangle Stainless Steel tube. |
First, we will calculate the sectional area in two parts, the orange-colored part area as A1, and green colored part area as A2.
Method: 1
First, we will calculate the total area inclusive of the hollow part, and then we will deduct the inner hollow portion (shown in green color) of the pipe.
Area a1 =[ B × D]
= [12.7 mm. × 25.4 mm.] = 322.58 square mm.
a1 = 0.000323 sq meter.
Area a2 = [{ B - (2T)} × { D - ( 2T)}]
= [{ 12.7 -( 2 × 1.5875)} × { 25.4 - (2 × 1.5875)}]
= [ 9.525 mm.× 22.225 mm.] = 211.693125 square mm.
( i.e. inner green hollow part )
a2 = 0.00021169 sq meter.
Now, the total sectional area
A = [a1 – a2]
= [0.000323 — 0.00021169] sq meter.
A = 0.00011131 square meter.
Note: We got the same area (A ) as calculated before.
Volume = [area × length]
= [0.00011131 ×6]
V = 0.00066786 cubic meter.
So, the weight of the hollow rectangular Stainless Steel 316 pipe of length 6 meters & Thickness Gauge 16.
= [volume × density]
= [0.00066786 × 7980]
= 5.3295228 kg.
_________________________________________________________________
For the calculation procedure, go through the following steps.
Let us consider a hollow rectangular mild steel tube or pipe of dimension 12.7mm × 25.4mm.× 1.27mm.
(0.5” x 1” x 0.05”) As shown in fig. below. Let us calculate the weight of the pipe having a 6-meter length.
| |
| Hollow Rectangle steel section. |
Here, thickness T = 1.27 mm. breadth B = 12.7 mm, depth D = 25.4 mm., and length L =6 m.
| |
| Hollow Rectangle Stainless Steel tube. |
First, we will calculate the sectional area in two parts, the orange-colored part area as A1, and green colored part area as A2.
Method: 1
First, we will calculate the total area inclusive of the hollow part, and then we will deduct the inner hollow portion (shown in green color) of the pipe.
Area a1 =[ B × D]
= [12.7 mm. × 25.4 mm.] = 322.58 square mm.
a1 = 0.000323 sq meter.
Area a2 = [{ B - (2T)} × { D - ( 2T)}]
= [{ 12.7 -( 2 × 1.27)} × { 25.4 - (2 × 1.27)}]
= [ 10.16 mm.× 22.86 mm.] = 232.2576 square mm.
( i.e. inner green hollow part )
a2 = 0.000232 sq meter.
Now, the total sectional area
A = [a1 – a2]
= [0.000323 — 0.000232] sq meter.
A = 0.000091 square meter.
Note: We got the same area (A ) as calculated before.
Volume = [area × length]
= [0.000091 ×6]
V = 0.000546 cubic meter.
So, the weight of the hollow rectangular Stainless Steel 316 pipe of length 6 meters & Thickness Gauge 18.
= [volume × density]
= [0.000546 × 7980]
= 4.35708 kg.
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Chart of Weight versus Gauge for Stainless Steel Hollow Pipe
The weight of the hollow square Stainless Steel 316 pipe (1.5” x 1.5”) of length 6 meters & Thickness Gauge 16. ------------ 11.1198 kg.
The weight of the hollow square Stainless Steel 316 pipe (1.5” x 1.5”) of length 6 meters & Thickness Gauge 18. ------------ 8.9775 kg.
The weight of the hollow rectangular Stainless Steel 316 pipe (0.5” x 1”) of length 6 meters & Thickness Gauge 16. ------------ 5.3295 kg.
The weight of the hollow rectangular Stainless Steel 316 pipe (0.5” x 1”) of length 6 meters & Thickness Gauge 18. ------------ 4.3570 kg.
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